Can you deduce the coefficient of restitution from impace force plot?

In summary, the conversation discusses the possibility of obtaining the coefficient of restitution from a plot showing the force of impact between two balls as a function of time. The area under the graph is related to the impulse, but does not directly provide information about the energy loss. The coefficient of restitution can be deduced by considering the compression and decompression phases separately and writing equations relating the speeds, momentum, and time.
  • #1
mokwana1221
8
0
If you have the impact force on the y-axis (in Newtons) and the time on the x-axis (in milliseconds), can you get the coefficient of restitution from just this? The plot is for the force of impact exchanged between two balls as a function of time.

I know the coefficient of restitution is the change of velocities of the balls just after impact divided by the change just before.

Thanks
 
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  • #2
welcome to pf!

hi mokwana1221! welcome to pf! :smile:

hint: what does the area under the curve represent? :wink:

(in the centre-of-mass reference frame, the coefficient of restitution is also the square-root of the ratio of kinetic energy after to kinetic energy before)
 
  • #3
hmm it gives us the impulse (Newton*Seconds) but can the coeff. of restitution be deduced from that? i am still kind of lost unfortunately
 
  • #4
also the area under the graph is triangular
 
  • #5
hopefully somebody can help me out before my final tomorrow, thanks guys
 
  • #6
I gather that the graph shows the force increasing linearly to a max then decreasing linearly to zero, the two slopes being different.
Intuitively, with restitution = 1 the two slopes would be the same. For less than 1, the second slope would be steeper. So it seems reasonable that the restitution is related to the ratio of the two areas.
Try considering the impact in those two phases. Let the two slopes be s1, s2, lasting t1, t2. The compression would peak, would it not, when the two bodies are at the same velocity? That should enable you to get enough equations.
 
  • #7
have you done integrals? area represents an integral
 
  • #8
tiny-tim said:
have you done integrals? area represents an integral
Hi tiny-tim.
I believe mokwana1221 established at post #3 that this much is understood. But that only gives the momentum exchange. It will not in itself say anything about the energy loss. See my previous post.
 
  • #9
i see now i am kind of getting it. yes the two slopes are different (and naturally the two areas under the graph as well, divided by the peak).

1) can we get a definitive quantitative answer using this graph for the coefficient of restitution?

2) if yes, would it be the ratio of the two slopes, or the ratio of the two areas under the peak?

this was under the professor's 'advance topics' for the exam as we did not cover it but i am putting in the extra mile just in case he throws it on the exam

thanks
 
  • #10
the area of the first triangle is 10 and the area of the second is 5, the ratio is .5.

the slope of the first triangle is 5 and the slope of the second triangle is 10. the ratio is also .5.

so my questions is, is the coefficient of restitution .5? or am i missing something? or is it not possible to get the coefficient of restitution from just this plot (if this is the case, what other data is needed to get the coefficient of restitution)?

thanks guys i feel like this is a simple problem and that i am just missing something.
 
  • #11
mokwana1221 said:
t
so my questions is, is the coefficient of restitution .5?
Perhaps - or it could be a more complicated relationship involving a square or square root. It cannot be guessed at. Try what I suggested: consider the compression and decompression phases separately so that the speeds are the same at peak compression. Write out equations relating speed, momentum, time, whatever for start and end of the two phases. See where it leads.
 
  • #12
i am truly at a dead end. i do not see how one can get energy or velocity from this graph since multiplying force (N) times time (milliseconds) equals impulse.

i have been thinking and googling this question since i first posted and joined the forum hours ago. i am stuck.
 
  • #13
can anyone help me with a last effort?

thanks, kwan
 
  • #14
Have you tried what I suggested? Consider the compression and decompression phases separately so that the speeds are the same at peak compression.
Let the masses m1, m2, start at speeds u1, u2 (same straight line), reach a common speed of v at peak compression, and finish at speeds w1, w2.
Let the impulse during compression (i.e. area under first triangle) be I and that during decompression be J.
Let the coefficient of restitution be R.
Write out equations relating the above:
- four for momentum
- one from the definition of coefficient of restitution
If you do all that you'll be surprised how easy it is to get the answer.
 

Related to Can you deduce the coefficient of restitution from impace force plot?

1. What is the coefficient of restitution?

The coefficient of restitution is a measure of the elasticity of a collision between two objects. It is used to determine the amount of energy lost or retained during the collision, with a higher coefficient indicating a more elastic collision and a lower coefficient indicating a more inelastic collision.

2. How is the coefficient of restitution calculated?

The coefficient of restitution is calculated by taking the ratio of the relative velocity of the objects after the collision to the relative velocity before the collision. This can be determined using the impact force plot, which shows the change in force over time during the collision.

3. Can the coefficient of restitution be deduced from an impact force plot?

Yes, the coefficient of restitution can be deduced from an impact force plot by analyzing the change in force over time during the collision. The slope of the force-time curve can be used to determine the relative velocities of the objects before and after the collision, which can then be used to calculate the coefficient of restitution.

4. Are there any limitations to deducing the coefficient of restitution from an impact force plot?

Yes, there are some limitations to using an impact force plot to deduce the coefficient of restitution. The accuracy of the calculation may be affected by factors such as the type of surface the objects are colliding on, the shape and size of the objects, and any external forces acting on the objects during the collision.

5. How is the coefficient of restitution used in scientific research?

The coefficient of restitution is used in a variety of scientific fields, such as physics, engineering, and sports science. It is used to understand the behavior of materials and objects during collisions, and to optimize designs for maximum efficiency and safety. It is also used in sports to analyze the performance of equipment and to prevent injuries.

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