Calculating Angular Speed for a Gravitational Field of 1.95g

In summary, the biologist wants to create a stronger gravitational field for her plants and places them on a rotating table in her lab at a distance of 42.3 cm from the axis of rotation. To find the angular speed needed for an effective gravitational field of 1.95 g, the equation a=w^2r is used. However, the answer of 6.72 rad/sec is incorrect and further guidance is needed to solve the problem.
  • #1
sona1177
173
1

Homework Statement


A biologist studying plant growth and wants to stimulate a gravitational field stronger than the Earth's. She places the plants on a horizontal rotating table in her laboratory (on Earth) at a distance of 42.3 cm from the axis of rotation. What angular speed will give the plants an effective gravitational field , geff, of magnitude 1.95 g? [Hint: Remember to account for Earth's gravitational field as well as the artificial gravity when finding the effective gravitational field.


Homework Equations


a=w^2r



The Attempt at a Solution


sq rt (a/r)=w
sq rt (1.95g/.423)=w=6.72 rad/sec
This is wrong according to my text. How do i do this problem?
 
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  • #2
sona1177 said:

Homework Statement


A biologist studying plant growth and wants to stimulate a gravitational field stronger than the Earth's. She places the plants on a horizontal rotating table in her laboratory (on Earth) at a distance of 42.3 cm from the axis of rotation. What angular speed will give the plants an effective gravitational field , geff, of magnitude 1.95 g? [Hint: Remember to account for Earth's gravitational field as well as the artificial gravity when finding the effective gravitational field.


Homework Equations


a=w^2r

The Attempt at a Solution


sq rt (a/r)=w
sq rt (1.95g/.423)=w=6.72 rad/sec
This is wrong according to my text. How do i do this problem?

...
 

Related to Calculating Angular Speed for a Gravitational Field of 1.95g

1. What is the formula for calculating angular speed for a gravitational field of 1.95g?

The formula for calculating angular speed for a gravitational field of 1.95g is ω = √(g/R), where ω is the angular speed, g is the gravitational acceleration, and R is the radius of the circular motion.

2. How does the gravitational field of 1.95g affect the angular speed?

The gravitational field of 1.95g will increase the angular speed compared to a gravitational field of 1g. This is because the force of gravity is stronger at 1.95g, causing the object to accelerate faster and thus increase the angular speed.

3. Can angular speed be negative for a gravitational field of 1.95g?

No, angular speed cannot be negative. It is always a positive value representing the rate of change of angular displacement over time.

4. How does the radius of circular motion affect the angular speed for a gravitational field of 1.95g?

The radius of circular motion has an inverse relationship with the angular speed. This means that as the radius decreases, the angular speed will increase and vice versa.

5. What unit is used to measure angular speed for a gravitational field of 1.95g?

The unit used to measure angular speed for a gravitational field of 1.95g is radians per second (rad/s).

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