Sorry, I misread the question, I thought it said [tex]y = \sqrt{3x} = (3x)^{1/2}[/tex] instead of [tex]y = \sqrt{3}x = (3)^{1/2} \cdot x[/tex]. I had a picture in my mind of drawing the tangent line at the origin and then calculating the angle of that with the x-axis, which could of course be done at any point. But since the function is just a straight line, it doesn't matter in this case (y' does not depend on x)Defennnder said:Why do you need to set x,y=0? The question is why the angle between the line graph and the axis is pi/3, not the angle between the point (0,0) and the x-axis, which doesn't make sense.
The angle between a function and an axis is the angle formed between the function and the x-axis or the y-axis. It measures the slope or direction of the function at a specific point.
2.The angle between a function and an axis is calculated using trigonometric functions such as tangent or arctangent. It can also be calculated by finding the slope of the function at a given point and using inverse trigonometric functions to determine the angle.
3.A positive angle between a function and an axis indicates that the function is increasing or going in an upward direction. A negative angle indicates that the function is decreasing or going in a downward direction.
4.Yes, the angle between a function and an axis can be greater than 90 degrees. This typically occurs when the function has a steep slope or is decreasing rapidly.
5.The angle between a function and an axis is often used in calculus to find the rate of change or slope of a function. It is also used in physics to determine the direction and magnitude of forces acting on an object.