I'm not understand what you mean by 'squared term by term'. What terms?
Again, I've noticed for the second beam doing what I did in my last post and dividing by 3 gives the correct solution.
This is what I thought would be the case, I did the following:
2EIU = M^2*s
U = 400,000^2 * 4 / (2 * 200x10^9 * 60.8x10^-6)
= 26.315 kJ
The solution states the answer is 8.772 kJ.
Which strangely enough is exactly a third of the answer I got it...
I can't work out the strain energy using the integral equation here, question (b)(i).
I've got the bending moment for the first beam as 400kN.
E and I are given, I'm guessing you can take '2EI' out of the integral and just integrate the M^2, is that correct?
Having problems with part (c) here, question is attached below in full.
Homework Statement
Using the equation 1/2 * Load * Displacement = Sum of (P^2 * L/2AE)
From the past questions I have the following info, these are also included in the solutions so are accurate:
A = 1x10^3 m^2
FAB =...
I am using the correct units and figures. The only figure that changes from working out the tensile stress and the compressive stress is the yc/yt value - correct?
yc = 400 - 118.33 = 211.67, using those figures doesn't bring the correct answer.
To clarify the max tensile stress = 4.98 MPa and...
y = 118.33 mm, too much working for this to type out.
Icc = 762.3 x 10^6 mm^44, using formula Icc = bh^3/12 + A1*h1^2 + A2*h2^2 + A3...
Bending moment is 3 m * 1000kN/m = 3kN load.
3 metres + 1/2 * 3 = 4.5 metres * 3kN
M = 13,500kNm
Apply σ = My / I as you say. Using yt = 118.33 to work out...
I do have the torque for each section, yes.
Still not getting the correct solution though. I'll take you through what I've done:
I have JL = 7.952 x 10^-8 and JR = 2.047 x 10^-7.
I have TR = shear stress * JR/ radius of right hand side = 732.6 Nm
I then calculated TL = (LR*JL / LL*JR) * TR...
Hi,
I'm struggling with finding the tensile stress at the mid-span of this beam. I've done the previous questions but have no idea how to begin with this one as I've never dealt with this question before.
What is the general method?
Correct answer is 1.66MPa.
Thanks.