- #1
smr101
- 72
- 0
Hi,
I'm doing question (c)(ii) in the image below, full working is provided below:
(c)(i) is 150kPa.
I = bh^3/12 - 2 * bh^3/12
(0.25 * 0.256^3)/12 - (2* (0.119 * 0.22^3)/12)
= 1.3831 x 10^-4 m^4
Q = y*A
= 0.119 * 0.018 * 0.250
= 5.355 x 10^-4 m^3
shear force = (150000 * 5.355 x 10^-4)/(1.3831 x 10^-4 * 0.25)
= 2.32 MPa
I know that the solution is shear force minimum = 48.4 MPa.
Where have I gone wrong?
Thanks!
I'm doing question (c)(ii) in the image below, full working is provided below:
(c)(i) is 150kPa.
I = bh^3/12 - 2 * bh^3/12
(0.25 * 0.256^3)/12 - (2* (0.119 * 0.22^3)/12)
= 1.3831 x 10^-4 m^4
Q = y*A
= 0.119 * 0.018 * 0.250
= 5.355 x 10^-4 m^3
shear force = (150000 * 5.355 x 10^-4)/(1.3831 x 10^-4 * 0.25)
= 2.32 MPa
I know that the solution is shear force minimum = 48.4 MPa.
Where have I gone wrong?
Thanks!