Recent content by Ayesha02

Its JEE Advanced Exam- for entry into undergrad engineering. and the molecule won't go upto the highest point as per KE because of viscosity isn't it? Viscosity'll retard it..

Probably. Its a competitive exam sum. how to develop thought process in such sums?

I figured out stokes law equation but I am unable to proceed further

Angular momentum conservation I got the answer:bow:

Skid initially, after some time rolls. Im assuming the surface is rough

I just did ##T## = 2/5 M R^2 * α which gives α =5μg/ 2R hence ##w_0(f)## = ##w_0(i)## - α t i.e 0= ##v_0##/2R - 5μg/ 2R *t hence i got t=4##v_0##/5μg (time when rotation ceases)

I found out the time when rotation ceases to be 4 ##v_0## /5*mew*g, where mew=coefficent of friction of surface but I am unable to plot the graph post that time

Yes dude got it thankyou:)

Ohh alright then

They can't go any further right, so shouldn't velocity be zero at that point?

Exactly my doubt! why do they have the same KE finally as well? @PeroK could you help us?

Nah! the final situation, as mentioned in the question, is when they're at min distance

ohh yaa! Another thing- why don't the bodies change velocity from the initial to the final?

an afterthought: why not conserve linear momentum?

Okay so i gather final angular momentum should be 2(m*v*6) is that right? Im still not able to figure out initial angular momentum