I know that haha, as it turns out, in my calculator for some reason you cannot use a and b as algebraic variables, it works perfectly fine using any other variable XD
Homework Statement
So, I know how to solve multiple equations using the cSolve method on the ti 89, but for some reason when I try to solve the following...
80a + 240b = 0 and (80+J79.975)a-80b = 50 by using the following syntax...
cSolve(80a + 240b = 0 and (80+J79.975)a-80b = 50...
Ok, so I understand this a lot better now after reading the following link...feeling pretty stupid at the moment...
http://www.mathsisfun.com/polar-cartesian-coordinates.html
I now understand that the measurement is in Degrees after taking Tangeant inverse of y/x.
My question now is, how do...
I don't really know what you mean by explaining the graph...It looks like an elipse, and I believe that polar coordinate measure real and imaginary parts of a number - That may be completely wrong. I am also fully aware that 5/0 is undefined I was just using the definitions presented in my book...
Well, for (5,0) the Polar Coordinates (r,theta) would be r = \sqrt{(5^2)+0^2} = 5
then the theta value would be Tan^{-1}(0)
or (-5,0) the Polar Coordinates (r,theta) would be r = \sqrt{(-5^2)+0^2} = 5
then the theta value would be Tan^{-1}(0)
for (0,5) the Polar Coordinates (r,theta) would be...
It's an arc in the first quadrant, with a y maximum of 5 and an x maximum of 5. I don't really know what you're asking, I apologize. This is holding me up on every problem I try, I have no clue how you get these values for theta...
This is what I got when I plotted it using wolfram, I assumed giving the max on the Y axis that it would be 5theta, I apologize if this is something simple, I am having a really difficult time understanding it
http://www.wolframalpha.com/input/?i=y+%3D+%2825-%28x%5E2%29%29%5E%281%2F2%29
Homework Statement
Change the Cartesian integral to an equivalent polar integral and evaluate
∫∫dydx
The bounds of the first integral (The outermost) are -5 to 5, and the bounds of the second (inner) are 0 to \sqrt{ 25-x^{2}}Homework Equations
∫∫dydx == ∫∫r(dr)(d\Theta)
x^{2}+y^{2}=r^{2}...
Homework Statement
I'm trying to Solve for an impulse response h(t) Given the excitation signal x(t) and the output signal y(t)
x(t) = 4rect(t/2)
y(t) = 10[(1-e-(t+1))u(t+1) - (1-e-(t-1))u(t-1)]
h(t) = ?
y(t) = h(t)*x(t) --> '*' meaning convolution!
I am unsure how to take the Fourier...
Homework Statement
Find the Impulse response of this system
3y[n]+4y[n-1]+y[n-2] = x[n] + x[n-1]
Homework Equations
Eigenvalues = -1/3 and -1
hc[n] = k1[-1/3]n+k2[-1]n
3h[n] +4h[n-1] +h[n-2] = δ[n] + δ[n+1]
The Attempt at a Solution
I know that normally we would plug in hc[n] for two...
So then after some algebraic manipulation I have
dh/dt= x(t)/A - h/RA
This still uses output flow as a parameter, which isn't what the question wants. I'm sorry that I'm so hung up on this problem