- #1
Gregg
- 459
- 0
Homework Statement
Calculate Youngs Modulus for the copper wire
We have done the experiment today, here is the data:
(KG)/F(N)/x(M)
0.1/0.1g/0.0
0.2/0.2g/0.0
0.3/0.3g/0.001
0.4/0.4g/0.001
0.5/0.5g/0.002
0.6/0.6g/0.003
0.7/0.7g/0.004
0.8/0.8g/0.005
0.9/0.9g/0.006
1.0/1.0g/0.009
1.1/1.1g/0.029
1.2/1.2g/0.053
1.3/1.3g/0.089
1.4/1.4g/0.160
Diameter = 0.27mm = 2.7x10-4Natural Length = 1m
Homework Equations
E = FL/AXgradient = F/X
E = gradient x L/A
The Attempt at a Solution
Radius = 1.4x10-4
A = (pi)(1.4x10-4)2
So i take the elastic region to be up to the 1kg load. The gradient of the line is (1g/0.009) = 1090.
The beginning length of the copper wire was 1mE = 1090 x 1 / AA = (pi)(1.4x10^-4)^2 E = 1090/(pi)(1.4x10^-4)^2E = 1.77x10^10 Pa = 17.7 GPa
According to the internet the young modulus is about 10 times larger than this. Have i gone wrong somewhere?