- #1
jokiemay
- 18
- 0
Homework Statement
I’m doing some basic young’s modulus homework and I think I’ve solved it but I want other people to give their answers to see if the match my own. Its young are of copper wire.
2. Homework Equations
E = stress over strain
Stress = applied force (F) over Cross sectional area (A)
Strain = Extension (e) over Original length (Lo)
A = 0.27mm
F = mxg
Lo = 1.788m
e = variable
My table of results are:
M / kg e / mm
0.100 0.45
0.200 0.94
0.300 1.40
0.400 1.97
0.500 2.46
0.600 3.29
0.700 4.12
0.800 5.00
0.900 6.36
1.000 8.223. The Attempt at a Solution
I’ve worked it out with 0.100kg
M (0.100) x g (9.81) = 0.981 so F = 0.981
Pi x 0.27 squared over 4 = 0.05725566 so A = 0.05725566
So stress = 17.13371733038794867967
e = 0.45
Lo = 1.788
So strain = 0.25167785234899
Young’s Modulus = 68.0779701927423389726993185
I know I’m going wrong somewhere so any help would be appreciated