- #1
ConfusedStudent
- 11
- 0
Consider this eq, It is balanced:
KCN+HCl=KCl+HCN
If a sample of 0.140g of KCN is treated with an excess of HCl, calculate the amount of HCN formed, in grams:
I just want to know if I did this right
0.140g KCN/65g KCN = x/27g HCN
and I got .058 g
Another probem:
Ammonium Nitrate decomposes to form n2o and h20, write a balanced eq. How many grams of n20 are formed if 0.46moles of Ammonium Nitrate is used in the reaction.
I did:
36.8 g NH4NO3/ 80g NH4NO3= x/44g N2O
I went ahead and converted mol to g in the beginning.
I got 20.24g N2O
One more question, :Calculate the number of moles of H3PO4 that will react with 5.55 mol of Ba(OH)2 to form Ba(H2PO4)2 and water
Now, I set up a mole ratios right?
KCN+HCl=KCl+HCN
If a sample of 0.140g of KCN is treated with an excess of HCl, calculate the amount of HCN formed, in grams:
I just want to know if I did this right
0.140g KCN/65g KCN = x/27g HCN
and I got .058 g
Another probem:
Ammonium Nitrate decomposes to form n2o and h20, write a balanced eq. How many grams of n20 are formed if 0.46moles of Ammonium Nitrate is used in the reaction.
I did:
36.8 g NH4NO3/ 80g NH4NO3= x/44g N2O
I went ahead and converted mol to g in the beginning.
I got 20.24g N2O
One more question, :Calculate the number of moles of H3PO4 that will react with 5.55 mol of Ba(OH)2 to form Ba(H2PO4)2 and water
Now, I set up a mole ratios right?