- #1
srfriggen
- 307
- 6
Someone please tell me what is wrong with this logic:
i = √-1
i2= √-1√-1 = √(-1)(-1) = √+1 = 1
But also i2 = (√-1)1/2= -1
i = √-1
i2= √-1√-1 = √(-1)(-1) = √+1 = 1
But also i2 = (√-1)1/2= -1
How does it come you know all the exotic corners out there? I'm flabbergasted every single time.micromass said:
The imaginary number i represents the square root of -1. When we raise i to the power of 2, we are essentially squaring the square root of -1, which results in -1.
This fact is based on the fundamental theorem of algebra, which states that every polynomial equation of degree n has n complex roots. In the case of i, we can see that i is a root of the polynomial equation x^2 + 1 = 0, which means that i^2 = -1.
The letter i was chosen by mathematician Leonhard Euler in the 18th century to represent the imaginary unit. It stands for "imaginary" and was chosen because i is the first letter of the word "imaginary" in Latin.
No, i is an imaginary number and cannot have a real value. It is defined as the square root of -1, which has no real solution. However, when i is multiplied by a real number, it does result in a complex number with both a real and imaginary component.
Imaginary numbers play a crucial role in many areas of mathematics, including complex analysis, differential equations, and signal processing. They allow us to solve certain equations and problems that would otherwise be impossible to solve using only real numbers. They also have practical applications in fields such as engineering and physics.