- #1
Jbreezy
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Hello, I can't seem to paste this in. So here is the link.
http://www.calcchat.com/book/Calculus-ETF-5e/
It is chapter 7, section 1, question 17.
Why are you adding ∫ [(x+2) +√4 -x] dx + ∫ 2(√4 -x) dx
?
I'm confused for 2 reasons. Why can you not just evaluate from -5 to 4? ( you will see the bounds I don't know how to put them on my integral here)
Why must you evaluate from -5 to 0 then from 0 to 4?
I understand the last term ∫ 2(√4 -x) dx this is 2 times because half is below the x axis.
But the first part...∫ [(x+2) +√4 -x] dx
Why would you add them. I can't seem to visualize why this would be. It seems I would find the area under x+2 then subtract that from the area under √4 -x.
Why not ??
Thanks,
J
http://www.calcchat.com/book/Calculus-ETF-5e/
It is chapter 7, section 1, question 17.
Why are you adding ∫ [(x+2) +√4 -x] dx + ∫ 2(√4 -x) dx
?
I'm confused for 2 reasons. Why can you not just evaluate from -5 to 4? ( you will see the bounds I don't know how to put them on my integral here)
Why must you evaluate from -5 to 0 then from 0 to 4?
I understand the last term ∫ 2(√4 -x) dx this is 2 times because half is below the x axis.
But the first part...∫ [(x+2) +√4 -x] dx
Why would you add them. I can't seem to visualize why this would be. It seems I would find the area under x+2 then subtract that from the area under √4 -x.
Why not ??
Thanks,
J
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