What is the Vertical Separation of Steel Balls in a Steady Fall?

In summary, the problem involves finding the vertical separation between two consecutive balls, given that they are falling at a rate of two per second and the lower one has dropped 3 meters after 0.782 seconds. Using kinematics equations, the time for the second ball is found to be 0.782 seconds and the upper one was dropped half a second earlier. The final solution involves subtracting half a second from the total time, resulting in the vertical separation between the two balls.
  • #1
Larrytsai
228
0

Homework Statement


Small Steel balls fall from rest through the opening at A at the steady rate of two per second. Find the vertical separation h of two consecutive balls when the lower one has dropped 3 meters.


Homework Equations


all kinematics equations


The Attempt at a Solution


I found the time it took for 1 ball to reach 3m which was 0.782 seconds, lost from here
 
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  • #2
Ok, so the lower one was dropped 0.728s ago and is 3m down. Then the upper one was dropped half a second earlier. Where is it?
 
  • #3
so then, i go 0.782/2 is the time for the second ball?
 
  • #4
Larrytsai said:
so then, i go 0.782/2 is the time for the second ball?

Nooo! 0.782s-(1/2)s. It was dropped 1/2 second earlier. They are falling at a rate of 2/second. Think about it.
 
  • #5
ohhh that makes sense, thanx
 

Related to What is the Vertical Separation of Steel Balls in a Steady Fall?

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