- #1
MAGNIBORO
- 106
- 26
hi, I try to calculate the integral
$$\int_{0}^{1}log(\Gamma (x))dx$$
and the last step To solve the problem is:
$$1 -\frac{\gamma }{2} + \lim_{n\rightarrow \infty } \frac{H_{n}}{2} + n + log(\Gamma (n+1)) - (n+1)(log(n+1))$$
and wolfram alpha tells me something about series expansion at ##n=\infty## of laurent series
http://www.wolframalpha.com/input/?...rmassumption={"C",+"limit"}+->+{"Calculator"}
I know a little about series of laurent, but I do not understand how they serve to solve limits
and expansion at ##n=\infty##.
$$\int_{0}^{1}log(\Gamma (x))dx$$
and the last step To solve the problem is:
$$1 -\frac{\gamma }{2} + \lim_{n\rightarrow \infty } \frac{H_{n}}{2} + n + log(\Gamma (n+1)) - (n+1)(log(n+1))$$
and wolfram alpha tells me something about series expansion at ##n=\infty## of laurent series
http://www.wolframalpha.com/input/?...rmassumption={"C",+"limit"}+->+{"Calculator"}
I know a little about series of laurent, but I do not understand how they serve to solve limits
and expansion at ##n=\infty##.