What is the ratio between the speeds before and after a short rocket thrust?

In summary, the satellite undergoes a short rocket thrust parallel to its velocity, resulting in a new elliptical orbit with an aphelion at Jupiter's orbital radius. The eccentricity of the orbit is calculated to be 0.677, and the perihelion speed can be determined using the vis-viva equation by setting the orbital radius to Earth's radius.
  • #1
alex3
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Homework Statement


A satellite is in a circular orbit around the sun, radius [tex]r_{e}[/tex], the radius of Earth's orbit. After a short rocket thrust parallel to its velocity, it is in a new orbit with aphelion at Jupiter's orbital radius, [tex]r_{j}[/tex]. What is the ratio of the speed's just before and after the thrust?

2. The attempt at a solution

I'm thinking like this:

  • The thrust is parallel to the velocity and is for a very short time, so the radii before and after the thrust are equal.
  • The aphelion is at Jupiter's orbital radius: the satellite is now describing an elliptical orbit, with an aphelion at Jupiter's orbital radius, and an perihelion at the thrust point; Earth's orbital radius.
  • We need the speed just after the thrust, so we need what the speed would be at the perihelion of the orbit.

Ok so far? I've worked out the eccentricity by using the following logic:

  • The sun is at one focus.
  • The major axis is the [tex]A = r_{j} + r_{e}[/tex], semi-major is [tex]a = \frac{A}{2}[/tex].
  • The distance from the centre of the ellipse to the focus is [tex]ae[/tex], so the eccentricity can be calculated using [tex]a - ae = r_{e}[/tex] and solving for [tex]e[/tex].

I calculated 0.677 for [tex]e[/tex], using

[tex]r_{j} = 7.8 \times 10^{11}[/tex]
[tex]r_{e} = 1.5 \times 10^{11}[/tex]

But how can I deduce the perihelion speed with this data?

EDIT

Is it just as simple as, by energy conservation, using the vis viva equation and setting r to r_e, or will I need some additional calculation?
 
Last edited:
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  • #2
Vis-viva should do fine.
 

Related to What is the ratio between the speeds before and after a short rocket thrust?

What is orbital perihelion speed?

Orbital perihelion speed refers to the speed at which an object in orbit around the sun is moving at its closest point to the sun, known as perihelion.

How is orbital perihelion speed calculated?

Orbital perihelion speed is calculated using the formula v = √(GM(2/r - 1/a)), where v is the speed, G is the gravitational constant, M is the mass of the sun, r is the distance from the object to the sun at perihelion, and a is the semi-major axis of the object's orbit.

What factors affect orbital perihelion speed?

The main factors that affect orbital perihelion speed are the mass of the sun, the distance from the object to the sun, and the shape of the object's orbit.

Why is orbital perihelion speed important?

Orbital perihelion speed is important because it affects the overall motion and stability of objects in orbit around the sun, and can also provide valuable information about the composition and structure of these objects.

How does orbital perihelion speed relate to other orbital parameters?

Orbital perihelion speed is related to other orbital parameters such as orbital velocity, orbital period, and orbital eccentricity. These parameters all work together to determine the shape and behavior of an object's orbit around the sun.

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