The Futur said:how do i calculate the kinetic energy?
The Futur said:Homework Statement
b) A person standing on the edge of a 100 m high cliff drops a 0.5 kg stone vertically downwards. Determine the final velocity of the stone after falling 100m, and its kinetic energy.
Homework Equations
Final velocity
v = √(2gx)
The Attempt at a Solution
final velocity
v = √(2gx)
v = √(2(0.5x9.8)100)
v= 31.3m/s
is that correct?
how do i calculate the kinetic energy?
The Futur said:so it will be
v = √(2gx)
v = √(2(9.8)100)
v= 44.27m/s ?
and no i don't know how to calculate the second part
The velocity of a falling rock depends on factors such as the height from which it is dropped, the mass and shape of the rock, and air resistance. It can be calculated using the equation v = √(2gh), where v is the velocity, g is the acceleration due to gravity (9.8 m/s^2), and h is the height in meters.
The mass of a rock does not directly affect its velocity when falling. However, a heavier rock will experience more gravitational force, which may cause it to fall faster than a lighter rock.
Yes, air resistance can significantly impact the velocity of a falling rock. As the rock falls, it pushes against air molecules, creating a force that opposes its motion and slows it down. The larger the surface area of the rock, the more air resistance it experiences, resulting in a lower velocity.
The terminal velocity of a falling rock is the maximum velocity it can reach as it falls through the air. It occurs when the force of gravity is balanced by the force of air resistance. The exact value of the terminal velocity depends on the mass and shape of the rock, as well as the density and viscosity of the air.
Yes, the velocity of a falling rock can exceed its terminal velocity in certain circumstances, such as in a vacuum or if the rock is falling from a great height. However, as the rock falls, it will eventually reach its terminal velocity and stop accelerating.