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Perodamh
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Homework Statement
A cylindrical rod of copper (E = 110GPa) having a yield strength of 240MPa is to be subjected to a load of 6660N. If the length of the rod is 380mm, what must be the diameter to allow an elongation of 0.5mm.
Homework Equations
E = stress/ strain
stress = Force/Area ; Area = pi*(diameter)/4
strain = elongation/original length
E= young's modulus = 110GPa = 110 * 10^9Pa
yield strength = 240MPa = 240 * 10^6Pa
Force = 6660N
elongation = 0.5mm
original length = 380mm
The Attempt at a Solution
I'm trying to understand relation between yield strength and young modulus.So far all i got from google is that it is the max stress a body goes through before plastic deformation occurs, but how do i plug that in anywhere? Thanks