What is the charge on a circular disc with a varying charge density?

In summary, the problem involves finding the total charge on a circular disc with a given charge density. The limits of integration are from 0 to a for ρ and 0 to 2∏ for φ. In the given example, ρ varies instead of being a constant value, so it can be integrated in this problem. The integral for this problem is ∫∫ρs0 (e^−ρ) sin^2(φ) dφdρ.
  • #1
technicolour1
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Homework Statement


Find the total charge on a circular disc of radius ρ = a if the charge density is given by
ρs = ρs0 (e^−ρ) sin2 φ C/m2 where ρs0 is a constant.
Are the two limits of integration from 0 -> a for ρ and 0->2∏ for φ? In the example given in the notes, ρ varies, instead of being a constant value. Does this mean that I cannot integrate ρ in this problem?

Homework Equations



Q = ∫ρdS

The Attempt at a Solution



Q = ∫∫ρs0 (e^−ρ) sin^2 (φ) dφdρ...
 
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  • #2
With the sin term it looks like there is as much positive as negative?

Edit, now I see the sin^2

Your integral looks doable.
 

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