Electric Field of a Charged Sphere?

In summary, a sphere of radius R with total charge Q has a volume charge density that decreases linearly from ρ_0 at the center to zero at the edge of the sphere. To find ρ_0, we can use the equation ρ = Q/V and integrate the charge density to relate it to the total charge. This results in ρ_0 = 3Q/πR^3. Inside the sphere, the electric field points radially outward with magnitude E = (Qr/4πε_0 R^3) (4 - 3 r/R), and outside the sphere (r > R), the electric field can be found using the same equation.
  • #1
ronk

Homework Statement


A sphere of radius R has total charge Q. The volume charge density (C/m^3) within the sphere is ρ = ρ_0 (1 - r/R).

This charge density decreases linearly from ρ_0 at the center to zero at the edge of sphere.

a. Show that ρ_0 = 3Q/πR^3.
b. Show that the electric field inside the sphere points radially outward with magnitude E = (Qr/4πε_0 R^3) (4 - 3 r/R).
c. Find the electric field outside the sphere (r > R).

Homework Equations


Volume of a Sphere: V = 4/3 πR^3.

The Attempt at a Solution


I knew that ρ = Q/V and could make this equal to our given value of ρ to find ρ_0, but I was unable to get rid of the 4 in the denominator to find ρ_0.
 
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  • #2
ronk said:
I knew that ρ = Q/V
This is incorrect. The sphere does not have uniform charge. You need to integrate the charge density to relate it to the total charge.
 

Related to Electric Field of a Charged Sphere?

1. What is an electric field of a charged sphere?

The electric field of a charged sphere is the force per unit charge exerted on a point in space around the sphere. It is a measure of the strength and direction of the electric force at any given point.

2. How is the electric field of a charged sphere calculated?

The electric field of a charged sphere can be calculated using the formula E = kQ/r^2, where E is the electric field, k is the Coulomb's constant, Q is the charge of the sphere, and r is the distance from the center of the sphere.

3. What is the direction of the electric field for a charged sphere?

The electric field for a charged sphere is directed radially outward from a positively charged sphere and radially inward for a negatively charged sphere. This means that the electric field lines point away from a positive charge and towards a negative charge.

4. How does the electric field of a charged sphere change as the distance from the center increases?

The electric field of a charged sphere decreases as the distance from the center increases. This is because the electric field strength follows an inverse square law, meaning it decreases by a factor of 1/r^2 as the distance increases.

5. Can the electric field of a charged sphere be affected by other nearby charges?

Yes, the electric field of a charged sphere can be affected by other nearby charges. The electric field at a point around the sphere will be the vector sum of the electric fields from all the charges present in the vicinity.

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