What is the ball's maximum height?

In summary: You have vi=10.8, vf=0, a=9.8 and d=14.24. So vi=10.8, vf=0, a=9.8, and d=14.24. You can solve for Vf^2 which is vertical speed final?so I plug in 0-2(10.8)=-21.6?In summary, the maximum height of the ball is 14.24 m, and its initial vertical speed is 10.8 m/s. The ball's acceleration due to gravity is 9.8 m/s^2, and the ball's height is the sum of its initial vertical speed and the acceleration.
  • #1
Casey314stl
15
0

Homework Statement


A ball is thrown upward.
What is its maximum height? Its initial
vertical speed is 10.8 m/s and the acceleration
of gravity is 9.8 m/s^2
Neglect air resistance.

Answer in units of m

Homework Equations



dfinal=dintial+vfinalΔt+ 1/2averageaccelerationΔt^2 or v^2final=v^2initial +2averageaccelerationΔd

The Attempt at a Solution


14.2463
 
Last edited:
Physics news on Phys.org
  • #2
No remember that since the object is traveling up it will have a negative speed therefore:

Vf^2=u^2+2is
 
  • #3
mtayab1994 said:
No remember that since the object is traveling up it will have a negative speed therefore:

Vf^2=u^2+2is
what does u and is stand for?
 
  • #4
u and v are vectors v is the final speed which in your case will be 0 because the kinetic energy will be 0 at the maximum height so you will be left with 0=speed of the ball -2(speed of gravity)s.
 
  • #5
so how do i use this to find the height?
 
  • #6
0=(initial speed)^2-2(speed of gravity)s then once you have this down just solve the equation.
 
Last edited:
  • #7
mtayab1994 said:
0=(initial speed)^2-2(speed of gravity)s than once you have this down just solve the equation.
I am solving for Vf^2 which is vertical speed final?
so I plug in 0-2(10.8)=-21.6?
 
  • #8
Casey314stl said:

Homework Statement


A ball is thrown upward.
What is its maximum height? Its initial
vertical speed is 10.8 m/s and the acceleration
of gravity is 9.8 m/s^2
Neglect air resistance.

Answer in units of m


Homework Equations



dfinal=dintial+vfinalΔt+ 1/2averageaccelerationΔt^2 or v^2final=v^2initial +2averageaccelerationΔd

The Attempt at a Solution


14.2463
Your second equation looks promising. In more compact terms:

vf2 = vi2 + 2*a*d

where vi is the initial velocity, vf the final velocity, a is the acceleration and d is the distance. The distance d is what you're looking for. What values will you assign to the other variables?
 

Related to What is the ball's maximum height?

1. What factors determine the ball's maximum height?

The ball's maximum height is determined by its initial velocity, the angle at which it is thrown, and the force of gravity.

2. How is the maximum height of a ball calculated?

The maximum height of a ball can be calculated using the equation: h = (v^2 * sin^2(theta)) / 2g, where h is the maximum height, v is the initial velocity, theta is the angle at which it is thrown, and g is the acceleration due to gravity (9.8 m/s^2).

3. Does air resistance affect the ball's maximum height?

Yes, air resistance can affect the ball's maximum height. Depending on the shape and speed of the ball, it can either increase or decrease the maximum height.

4. How does the mass of the ball affect its maximum height?

The mass of the ball does not affect its maximum height, as long as the initial velocity and angle remain constant. However, a heavier ball may lose more energy to air resistance and therefore have a slightly lower maximum height compared to a lighter ball.

5. Can the ball's maximum height change if it is thrown on different planets?

Yes, the ball's maximum height will change on different planets because the force of gravity varies on each planet. The maximum height can be calculated using the same equation, but with the corresponding value for acceleration due to gravity on that planet.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
323
  • Introductory Physics Homework Help
2
Replies
38
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
Replies
14
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
265
Back
Top