- #1
03cobra 87gn
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Homework Statement
heating .50kg of diet cola mostly water, by
adding steam. How much steam should be bubbled in so final temp. is 90 deg C
Homework Equations
what i tired so far downt know if it the right way to go abotu the problem is specific heat capacity Q=mc detlaTE tot of the system =0 so Q1+Q2 =0
The Attempt at a Solution
so i did Q(cola)+Q(steam)=0
M(cola)*C(cola)*(Tf-Ti)+M(steam)*C(steam)*deltaT
500g*1 cal/g*deg C (90-20 deg C) + M steam * .480 cal/g*deg C * delta T
the last delta T on the right do i keep that in or do i use the temp. of steam in my book?
if i use 7 deg C for the stema delta T i get 1.04 kg of steam
if i use the 110 deg C which is under the specific heat of steam i get .662 kg
i don't know which or if either one are right so any help would be greatly appreciated
thanks