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SpY]
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what has "radio" got to do with this activity?
Probably sounds silly, but what has "radio" got to do with this activity?
I don't know if I'm interpreting this guy's formula right (http://www.hps.org/publicinformation/ate/q8270.html) so can someone confirm this expression for half life:
[tex]A= \frac{C_R}{CD}[/tex]
[tex]=kN[/tex]
[tex]= \Bigg( \frac{ln(2)}{T_\frac{1}{2}} \Bigg) \Bigg( \frac{m_0}{A_r} N_A \Bigg) [/tex]
Where [tex]C_R[/tex] is the count rate, [tex] C_D [/tex] the counts per disintegration, k the decay constant, N the number of radioactive atoms, [tex]T_\frac{1}{2} [/tex] the half life, [tex]m_0 [/tex] the original mass of the pure substance [tex] A_R [/tex]the atomic weight [tex] N_A [/tex] Avogadro's number. (bad latex sorry)
If not, can you help me find a way to find the half life of a long lived radionuclide?
Probably sounds silly, but what has "radio" got to do with this activity?
I don't know if I'm interpreting this guy's formula right (http://www.hps.org/publicinformation/ate/q8270.html) so can someone confirm this expression for half life:
[tex]A= \frac{C_R}{CD}[/tex]
[tex]=kN[/tex]
[tex]= \Bigg( \frac{ln(2)}{T_\frac{1}{2}} \Bigg) \Bigg( \frac{m_0}{A_r} N_A \Bigg) [/tex]
Where [tex]C_R[/tex] is the count rate, [tex] C_D [/tex] the counts per disintegration, k the decay constant, N the number of radioactive atoms, [tex]T_\frac{1}{2} [/tex] the half life, [tex]m_0 [/tex] the original mass of the pure substance [tex] A_R [/tex]the atomic weight [tex] N_A [/tex] Avogadro's number. (bad latex sorry)
If not, can you help me find a way to find the half life of a long lived radionuclide?
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