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ibysaiyan
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Homework Statement
Hi,
The question itself doesn't sound too complicated i some-how got the asnwer,just wondering if its correct or not.
Question is:A radioactuve isotope wuith a half-life of 1.6x10^5 s disintegrates to form a stable product.A pure sample of 'x' is prepared with an initial activity of 25000Bq.
Caclulate the activity of the sample after week one.
Homework Equations
A= Ao e^-lamdba (t)
T(1/2)= Ln2 /lamda.
The Attempt at a Solution
I used initial activity as 25k bq now i thought activity to be in /s? i don't know here is what I've done.
A= Ao e^-lamdba (t)
LnA = LnA0 - (lamda)x T
LnA = ln(25000)-(4.33x10^-6 x 604.8x10^3)
A = 1822. <--- would the units be in s^-1?
Again thanks for your input =}.