- #1
vorcil
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Homework Statement
Hi, I need to figure out what happens to this equation in the limits
[tex] E = \frac{1}{4\pi\epsilon_0} \frac{2\lambda L}{z \sqrt{z^2+L^2}} [/tex]
in the two different cases
that z>>L
and when L -> infinity
(note this equation was derived from finding the electric field da distance z, above the midpoint of a straight line segment of length 2L, which carries a uniform line charge of [tex] \lambda [/tex]
The Attempt at a Solution
for the case when, z>>L I can see how the L term becomes insignificant in the square root on the bottom,
and so the equation would just become
[tex]\frac{1}{4\pi\epsilon_0} \frac{2\lambda L}{z^2} [/tex]
but for the case when L approaches infinity, what do I do?
the squareroot of a L^2 +z^2 == L?
does that mean the L can just be canceled out?
[tex] \frac{1}{4\pi\epsilon_0} \frac{2\lambda L}{z *L} [/tex]
and the equation becomes?
[tex] \frac{1}{4\pi\epsilon_0} \frac{2\lambda}{z} [/tex]
i'm not sure if I'm allowed to since the Z was the distance from the midpoint of the line,
the first one makes sense since it just becomes a point charge of 2lambda L
but the second case, I'm not too sure what it becomes