Welcome to PhysicsForums.Mimyo said:
Professor just gave me the picture, since we can't do the experiment due to COVID 19. So this is the result of the "equipotential line experiment". The picture I posted is the 1/4 of the result and the original one (That I have to complete) is below. Line of electric force flows from + to -, and you can see the ( + ) in the picture.berkeman said:Welcome to PhysicsForums.
The problem statement and the graph/drawing are very confusing. What is the full problem statement? What is at the origin? Charge? Current? A point of something or a distribution of line charge or something?
And what did the blank diagram look like before you started trying to draw lines on it? Were the long straight lines at angles there before, or did you draw those with a ruler? Were only the dotted lines in arcs on the drawing before, and all of the rest of the lines are yours?
The equation for the symmetry of equipotential lines is V(x,y,z) = constant, where V represents the potential and (x,y,z) represents the coordinates on the equipotential line.
The symmetry of equipotential lines is directly related to electric fields. Equipotential lines are always perpendicular to electric field lines, and the electric field is strongest where the equipotential lines are closest together.
Yes, the symmetry of equipotential lines can be used to calculate the electric potential at a point. By knowing the potential at one point on an equipotential line, the potential at any other point on that line can be determined using the equation V(x,y,z) = constant.
In the presence of a point charge, the symmetry of equipotential lines is disrupted. The equipotential lines will be closer together near the point charge and will spread out as they move away from the charge.
Yes, there are other factors that can affect the symmetry of equipotential lines. These include the presence of multiple point charges, the shape and size of conductors, and the distance between charges or conductors.