- #1
Claire84
- 219
- 0
Hey there, I'm trying to work out all the solutions of z for ln(z)=-1. I let -1=ln|z| so then I took exponentials of both sides so I had e^(-1)=|z| so 1/e would equal z. I wasn't sure about having z also equal to -1/e, because since ln(z) = ln|z| + iarg(z) then for z=-1/e then the arg (z) would have to be pi or something... If anyone could help it would be great cos with the way the question has been asked about finding ALL the solutions, I think I'm missing something here. Thanks.