- #1
sagaradeath
- 12
- 0
Urgent! Question Problem! Please Help!
1. Homework Statement [/b]
In the sum A-> + B-> = C->, A-> vector has a magnitude of 13.8 m and is angled 44.0° counterclockwise from the +x direction, and vector C-> has a magnitude of 16.8 m and is angled 18.8° counterclockwise from the -x direction. What are (a) the magnitude and (b) the angle (relative to +x) of B->? State your angle as a positive number.
2. Homework Equations [/b]
3. The Attempt at a Solution
I don't know if its right or not. :(
sin(44)13.8 = 9.58628 for A
sin(18.8)16.8 = 5.41406368 for C
cos(44)13.8=9.926889245 for A
cos(18.8)16.8=15.90370757 for C
that's the two components of A and C. since you're trying to find B
it's C - A = B.
in the x direction: 5.41406368 - 9.58628 = -4.172
in the y direction: 15.90370757 - 9.926889245 = 5.976
The magnitude is simply sqrt (x component^2 + y component^2) = 7.288
the angle relative to +x is tan^-1(x component/y component) = tan^-1(-4.172/5.976) = -34.9 degrees.
1. Homework Statement [/b]
In the sum A-> + B-> = C->, A-> vector has a magnitude of 13.8 m and is angled 44.0° counterclockwise from the +x direction, and vector C-> has a magnitude of 16.8 m and is angled 18.8° counterclockwise from the -x direction. What are (a) the magnitude and (b) the angle (relative to +x) of B->? State your angle as a positive number.
2. Homework Equations [/b]
3. The Attempt at a Solution
I don't know if its right or not. :(
sin(44)13.8 = 9.58628 for A
sin(18.8)16.8 = 5.41406368 for C
cos(44)13.8=9.926889245 for A
cos(18.8)16.8=15.90370757 for C
that's the two components of A and C. since you're trying to find B
it's C - A = B.
in the x direction: 5.41406368 - 9.58628 = -4.172
in the y direction: 15.90370757 - 9.926889245 = 5.976
The magnitude is simply sqrt (x component^2 + y component^2) = 7.288
the angle relative to +x is tan^-1(x component/y component) = tan^-1(-4.172/5.976) = -34.9 degrees.