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Mutaja
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Homework Statement
Find the volume of the solid of revolution when we rotate the area limited by the x-axis and the function f(x) = 1 - cosx where x e [0, 2∏] once around the y-axis?
The Attempt at a Solution
In my notes I have the following equation:
V = ∫ 2∏x f(x) dx
If I put in my limits (upper limit 2∏, lower limit 0) and my function I get the following:
V = 2∏ ∫x(1-cos(x)) dx
V = 2∏ ∫x - xcos(x) dx
V = 2∏[[itex]\frac{x^2}{2}[/itex] - (xsin(x)+cos(x))]
V = 2∏ [[itex]\frac{x^2}{2}[/itex] - (∏sin(∏) + cos(∏)] - 2∏ [[itex]\frac{0^2}{2}[/itex] - (0sin(0) + cos(0)]
Since ∏ sin(∏) = 0, cos(∏) = -1 , 0sin(0) = 0 and cos(0) = 1 I get the following:
V = 2∏ ([itex]\frac{∏^2}{2}[/itex]) - 2∏ + 1
V = ##2∏^3## - 4∏ + 2
Is this correct? Am I using the correct formulas/equations?
Please let me know if there is something I need to explain better. Any help and guiding is massively appreciated. Thanks.
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