- #1
whitehorsey
- 192
- 0
1. See Attachment
2. None
3. a. I found the volume of the box which is like this
x(24-2x)(24-2x)
= x(576-96x+4x2)
= 4x3 - 96x2 + 576x
= 4(x3 -24x2 +144x)
but how do I find the domain?
b. and c.How do I use my graphing calculator to graph this because when I graph I only get a line?
1. Find all solutions of the equation.
2cos2[tex]\Theta[/tex] - [tex]\sqrt{3}[/tex] = 0
2. None
3. 2cos2[tex]\Theta[/tex] - [tex]\sqrt{3}[/tex] = 0
= 2cos2[tex]\Theta[/tex] = [tex]\sqrt{3}[/tex]
= cos 2[tex]\Theta[/tex] = [tex]\sqrt{3}[/tex]/2
= 2[tex]\Theta[/tex] 30, 330, 390, 690
= [tex]\Theta[/tex] = 15, 165, 195, 345 degrees
Did I do this right?
Thank You!
2. None
3. a. I found the volume of the box which is like this
x(24-2x)(24-2x)
= x(576-96x+4x2)
= 4x3 - 96x2 + 576x
= 4(x3 -24x2 +144x)
but how do I find the domain?
b. and c.How do I use my graphing calculator to graph this because when I graph I only get a line?
1. Find all solutions of the equation.
2cos2[tex]\Theta[/tex] - [tex]\sqrt{3}[/tex] = 0
2. None
3. 2cos2[tex]\Theta[/tex] - [tex]\sqrt{3}[/tex] = 0
= 2cos2[tex]\Theta[/tex] = [tex]\sqrt{3}[/tex]
= cos 2[tex]\Theta[/tex] = [tex]\sqrt{3}[/tex]/2
= 2[tex]\Theta[/tex] 30, 330, 390, 690
= [tex]\Theta[/tex] = 15, 165, 195, 345 degrees
Did I do this right?
Thank You!