Visualizing a Triple Integral Bounded by Planes

In summary, the given function is xyz2 and the volume V is bounded by y=1-x, z=0, and z=y. The limits of integration are x from -1 to 1, y from 0 to (1-x^2), and z from 0 to y. The problem requires a graph to represent the region to be integrated, which includes two vertical lines at x=-1 and x=1, a parabola y=1-x^2, and a plane z=y. However, one more bound is needed for z in order for the region to be bounded. The upper limit for z is currently y, but it is unclear if this is the complete bound for z.
  • #1
arl146
343
1

Homework Statement


the function is xyz2

V is bounded by y=1-x, z=0, and z=y.


The Attempt at a Solution



the limits are:

x is from -1 to 1 ?
y is from 0 to (1-x^2) ?
z is from 0 to y ?

the question asks for a picture ... how should that look? there are points on (1,0,0), (-1,0,0), (0,0,1) and (0,1,0) ?
 
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  • #2
You need one more bound.
This is likely x=c.
c is come constant
 
  • #3
i don't get that, i mean like how that helps
 
  • #4
What you are likely to get is a tetrahedron, which requires 4 faces.
The 4 faces are your 4 bounds, which are planes.
But you have wrote 3 bounds, what about the 4th?
 
  • #5
arl146 said:

Homework Statement


the function is xyz2

V is bounded by y=1-x, z=0, and z=y.


The Attempt at a Solution



the limits are:

x is from -1 to 1 ?
y is from 0 to (1-x^2) ?
z is from 0 to y ?

the question asks for a picture ... how should that look? there are points on (1,0,0), (-1,0,0), (0,0,1) and (0,1,0) ?
Draw a graph. x is from -1 to 1 so draw two vertical lines at x=-1 and x= 1. y if from 0 to 1- x^2 so draw the the line y= 0 and the parabola y= 1- x^2. The region to be integrated is inside that parabola above y= 0. Finally, the plane z= y crosses the y-axis up to (x, 1, 1) and your three dimensional region comes up to that. As Quinzio said, you need another bound on z or that region is not bounded. As it is, z could go up from that plane to infinity of down to negative infinity. Is there another limit, perhaps 0, on the z-integration?
 
  • #6
Well I just gave what the problem gave. The upperimit for z is y?
 

Related to Visualizing a Triple Integral Bounded by Planes

1. What is a triple integral and when is it used?

A triple integral is a mathematical tool used in multivariable calculus to calculate the volume of a three-dimensional region. It is used when the volume of a solid cannot be easily calculated with a single or double integral.

2. What is the process for setting up a triple integral?

The process for setting up a triple integral involves determining the limits of integration for each variable, identifying the appropriate integrand, and then integrating over the three variables in the correct order. This order is typically from the outermost variable to the innermost variable.

3. How do I determine the limits of integration for a triple integral?

The limits of integration for a triple integral depend on the shape and orientation of the three-dimensional region being integrated. They can be determined by visualizing the region and breaking it down into smaller, simpler shapes, or by using equations or geometric principles to determine the boundaries of the region.

4. Can a triple integral be set up in any order?

No, the order of integration for a triple integral is important and cannot be changed. Changing the order can result in different values for the integral and may make the integration more difficult or impossible.

5. What are some common applications of triple integrals?

Triple integrals have many applications in physics, engineering, and economics. They are commonly used to calculate the volume and mass of irregularly shaped objects, the center of mass of a three-dimensional object, and the volume of a fluid flow. They can also be used to solve optimization problems and calculate probabilities in statistics.

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