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johannaposey
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Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 2.5×104 when at a distance of 2.3×1011 from the center of the sun, what is its speed when at a distance of 5.9×1010 .
Using Kepler's Law T2 is proportional to R3
T2/R3 is a constant (C)
-->T= (2*[itex]\pi[/itex]*R)/v -->T2= (4*[itex]\pi[/itex]2*R2)/v2
therefore
C= (4*[itex]\pi[/itex]2)/(R*v2)
since
4*[itex]\pi[/itex]2 is a constant C= 1/(R*v2)
therefore
R1*(v1)2=R2*(v2)2
Plugging in the variables, I got 4.93x104, but that answer was wrong. Why?
Using Kepler's Law T2 is proportional to R3
T2/R3 is a constant (C)
-->T= (2*[itex]\pi[/itex]*R)/v -->T2= (4*[itex]\pi[/itex]2*R2)/v2
therefore
C= (4*[itex]\pi[/itex]2)/(R*v2)
since
4*[itex]\pi[/itex]2 is a constant C= 1/(R*v2)
therefore
R1*(v1)2=R2*(v2)2
Plugging in the variables, I got 4.93x104, but that answer was wrong. Why?
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