- #1
thakid87
- 8
- 0
Not exactly a homework question, even though it is related to my homework...
So, the law is:
(sin A/a) = (sin B/b) = (sin C/c)
So, in certain problems we have to manipulate this law. For example our givens include angle C and side c.
(sin A/a) = (sin C/c)
a would have to equal [(c sin A)/sin C]
Why can't a = [sin C/(c sin A)]
If someone can explain this, I'd greatly appreciate it.
Thanks.
So, the law is:
(sin A/a) = (sin B/b) = (sin C/c)
So, in certain problems we have to manipulate this law. For example our givens include angle C and side c.
(sin A/a) = (sin C/c)
a would have to equal [(c sin A)/sin C]
Why can't a = [sin C/(c sin A)]
If someone can explain this, I'd greatly appreciate it.
Thanks.
Last edited: