Understanding the Formula for Exponential Decay of Voltage

In summary, the conversation is about understanding a formula for exponential decay of voltage. The formula is t=T1n(E/Vl) and an example is given. The person is struggling to understand where the value of 2.38 comes from and how the natural log (LN) fits into the formula. It is also mentioned that the formula was discussed in a previous thread and the solution was to use a scientific calculator. The conversation ends with the person thanking the expert for their help.
  • #1
bryanehli
5
0
Please Help!

This is based on the time at any point on the curve during exponential decay of voltage.

Could someone explain to me this formula?

t=T1n(E/Vl)

example:

t=(7.5ms)1n(20v/14.57v)=2.38ms.

I get 20/14.57=1.372683596
(7.5)(1.372683596)=10.29512697
where and how do you get 2.38, where does the 1n fall in and how? is there a numerical value for this statement? Please help?
 
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  • #2
Please don't multiple post the same question. Your question was answered in your original thread:

https://www.physicsforums.com/showthread.php?t=237561

What you are writing as 1n is actually LN, or the natural log. It is a button on your scientific calculator.
 
  • #3
it still does not work!
 
  • #4
bryanehli said:
it still does not work!

Yes it does.

t=(7.5ms) * LN(20v/14.57v) = 2.38ms.

Divide 20/14.57, take the natural log, then multiply by 7.5. I get 2.375something.
 
  • #5
Thank You!
 

Related to Understanding the Formula for Exponential Decay of Voltage

1. What is exponential decay of voltage?

Exponential decay of voltage is a phenomenon in which the voltage of a system decreases over time at a rate that is proportional to its current voltage. This occurs in systems that have a capacitor, which stores and releases electrical energy, and a resistor, which limits the flow of current.

2. Why does exponential decay occur in voltage?

Exponential decay occurs in voltage because of the relationship between the capacitor and resistor in a system. As the capacitor releases its stored energy, the current flowing through the resistor decreases, causing the voltage to decrease as well.

3. What factors affect the rate of exponential decay in voltage?

The rate of exponential decay in voltage is affected by the values of the capacitor and resistor, as well as the initial voltage of the system. A larger capacitor will result in a slower decay rate, while a larger resistor will result in a faster decay rate. Additionally, a higher initial voltage will result in a faster decay rate.

4. How is the rate of exponential decay calculated?

The rate of exponential decay in voltage can be calculated using the time constant, which is equal to the product of the resistance and capacitance in the system. The formula for calculating the rate of decay is V(t) = V0e^(-t/RC), where V(t) is the voltage at time t, V0 is the initial voltage, R is the resistance, C is the capacitance, and e is the mathematical constant.

5. What are some real-world applications of exponential decay of voltage?

Exponential decay of voltage has numerous real-world applications, including in electronics such as capacitors and RC circuits, as well as in natural phenomena such as radioactive decay. It is also used in various technologies, such as in battery charging and discharging, and in medical devices like defibrillators and pacemakers.

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