- #1
icystrike
- 445
- 1
2008
Summation (-1)[tex]^{i}[/tex] [tex]\frac{i^2+i+1}{i!}[/tex]
i=1
I guess I am suppose to apply the summation rule
and i got (-1)[tex]^{i}[/tex] [tex]\frac{n(n+1)(n+2)+3n}{3i!}[/tex]
Summation (-1)[tex]^{i}[/tex] [tex]\frac{i^2+i+1}{i!}[/tex]
i=1
I guess I am suppose to apply the summation rule
and i got (-1)[tex]^{i}[/tex] [tex]\frac{n(n+1)(n+2)+3n}{3i!}[/tex]