Understanding Stress in Pipe Walls: Impact of Internal Air Pressure

In summary: The r, or r² term disappears for zero pressure difference.σr = [(Pi·Ri² - Po·Ro²) / (Ro² - Ri²)] + [Ri²·Ro²· (Po - Pi) / ( r²· (Ro² - Ri²))]... and the first term simplifies to -Pi. Or -Po, same thing. Which means radial compression is simply the common pressure on both sides, as expected.
  • #1
Ebi
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Consider a pipe. The pipe is not crushed by the air pressure because the same air pressure is acting from inside the pipe. But this means that the material of the pipe is being compressed on both sides by some air pressure. So is it correct to say that the through-thickness stress in the pipe would be the same as the air pressure?
 
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  • #2
yes
 
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  • #3
Yes, but its insignificant. Most material strengths are rated in MPa. The measly 101.325 kPa we've got as air pressure is hardly a challenge. Thats why it's just ignored...
 
  • #4
The wall will be thickest when the open pipe is in a vacuum.

The wall will become progressively thinner as the open pipe is subjected to greater hydrostatic pressures.
 
  • #5
Just like for every other material around us (with very few exceptions), yes.
 
  • #7
Baluncore said:
The wall will be thickest when the open pipe is in a vacuum.

The wall will become progressively thinner as the open pipe is subjected to greater hydrostatic pressures.

Thanks for your response. What you said is intuitive but if you look at link below, for Pi=Po, it seems stress through the thickness varies with the radius r.
https://www.engineeringtoolbox.com/stress-thick-walled-tube-d_949.html

I am not sure if I am missing something.
 
  • #8
If you go to the calculator at the bottom of the referenced page, and enter zero internal and external pressure, you get zero stress.
 
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  • #9
Ebi said:
Thanks for your response. What you said is intuitive but if you look at link below, for Pi=Po, it seems stress through the thickness varies with the radius r.
The r, or term disappears for zero pressure difference.
σr = [(Pi·Ri² - Po·Ro²) / (Ro² - Ri²)] + [Ri²·Ro²· (Po - Pi) / ( r²· (Ro² - Ri²))]
 
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  • #10
... and the first term simplifies to -Pi. Or -Po, same thing. Which means radial compression is simply the common pressure on both sides, as expected.
 
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Related to Understanding Stress in Pipe Walls: Impact of Internal Air Pressure

1. What is stress in pipe walls?

Stress in pipe walls refers to the amount of force or pressure exerted on the walls of a pipe due to internal factors, such as the flow of fluids or gases inside the pipe.

2. How does internal air pressure affect stress in pipe walls?

Internal air pressure can increase the stress in pipe walls by exerting a force on the walls. This can lead to deformation or failure of the pipe if the stress exceeds the strength of the material.

3. What are the factors that contribute to stress in pipe walls?

Apart from internal air pressure, other factors that can contribute to stress in pipe walls include external loads, temperature changes, and changes in the material properties of the pipe.

4. How can stress in pipe walls be measured?

Stress in pipe walls can be measured using strain gauges or pressure sensors placed on the surface of the pipe. These devices can accurately measure the amount of stress being exerted on the walls.

5. What are the potential consequences of high stress in pipe walls?

High stress in pipe walls can lead to pipe failure, which can result in leaks, ruptures, or even explosions. It can also cause deformation or buckling of the pipe, affecting its structural integrity and functionality.

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