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For future reference, it's much preferred to include the problem directly in the post, rather than making people download a file to just read it.2.4 Let [itex]\psi(x)[/itex] be a properly normalised wavefunction and [itex]Q[/itex] an operator on wavefunctions. Let
[itex]\{q_r\}[/itex] be the spectrum of [itex]Q[/itex] and [itex]\{u_r(x)\}[/itex] be the corresponding correctly normalised eigenfunctions.
Write down an expression for the probability that a measurement of [itex]Q[/itex] will yield the value [itex]q_r[/itex]. Show that [itex]\sum_r P(q_r|\psi) = 1[/itex]. Show further that the expectation of [itex]Q[/itex] is [itex]\langle Q\rangle \equiv \int_{-\infty}^{\infty}\psi^{*}\hat{Q}\psi\mathrm{d}x[/itex].
This problem makes no use of Dirac notation at all. I'd suggest just thinking about eigenfunctions and eigenvalues, don't worry about states.bon said:Ok so basically a bit confused about notation..
does |psi> = sum over all r of ar |ur> ?
any help would be great..thanks
diazona said:Here's the problem statement from the PDF file:
For future reference, it's much preferred to include the problem directly in the post, rather than making people download a file to just read it.
This problem makes no use of Dirac notation at all. I'd suggest just thinking about eigenfunctions and eigenvalues, don't worry about states.
Well, you're right thatbon said:Ooh ok that kind of makes sense but let me put my point another way:
|psi> = integral over all x dx psi(x) |x>
so |psi><psi| = integral over all x dx psi*(x) psi(x) = 1 since psi(x) is a normalised wavefunction...
What's wrong with this argument?
No, I don't think that's right.bon said:Oh i see where i went wrong. Am i right in thinking |psi><psi| = |x><x|? Why does this hold?
You actually just need to swap the order of the factors on the RHS:bon said:Oh ok sure - I'm just saying that if |<qr|psi>|^2 is the probability that a measurement of Q will yield value qr, then for the next part i.e. sum over all r of P(qr|psi) = sum over all r of |<qr|psi>|^2.
But |<qr|psi>|^2. = |<qr|psi><psi|qr>|
diazona said:You may be thinking of the completeness criterion, which says that
[tex]\sum_i |\phi_i\rangle\langle\phi_i| = 1[/tex]
if and only if the states [itex]\{|\phi_i\rangle\}[/itex] form a complete basis - in other words, if and only if any arbitrary state can be expressed as a linear combination of the [itex]|\phi_i\rangle[/itex]'s. (That equation may be useful to you in solving this problem )
[itex]\langle \psi | \psi \rangle[/itex] and [itex]|\psi\rangle\langle\psi|[/itex] are two different mathematical objects.bon said:Ooh ok that kind of makes sense but let me put my point another way:
|psi> = integral over all x dx psi(x) |x>
so |psi><psi| = integral over all x dx psi*(x) psi(x) = 1 since psi(x) is a normalised wavefunction...
What's wrong with this argument?
Dirac notation, also known as bra-ket notation, is a mathematical notation used to describe quantum states and operations in quantum mechanics. It was developed by physicist Paul Dirac and is widely used in quantum physics and quantum information theory.
Dirac notation is useful because it provides a concise and elegant way to write and manipulate complex mathematical expressions in quantum mechanics. It also allows for a more intuitive understanding of quantum states and operations, making it easier to solve homework problems and perform calculations.
The basic elements of Dirac notation are the bra, represented by 〈a|
, which is the conjugate transpose of a column vector, and the ket, represented by |b〉
, which is a column vector. The inner product of a bra and a ket is represented by 〈a|b〉
, and the outer product of a bra and a ket is represented by 〈a|b〉〈b|a〉
.
To perform operations using Dirac notation, you can use the properties of bras and kets, such as linearity and distributivity, and apply them to the mathematical expressions. You can also use the inner and outer product to calculate the inner product of two states or the outer product of two operators.
Some common mistakes to avoid when using Dirac notation include forgetting to take the conjugate transpose of a bra, not using the correct notation for inner and outer products, and not properly understanding the properties of bras and kets. It is also important to double check calculations and make sure all mathematical operations are performed correctly.