- #1
AStaunton
- 105
- 1
trying to solve the following integral by substitution but having trouble:
[tex]\int\cos^{5}7x\sin7xdx[/tex]
I attempted to set [tex]u=\cos^{5}7x[/tex] and ended up with (by chain rule...which I hope is correct!):
[tex]du=-35\cos^{4}7x\sin7xdx[/tex]
This doesn't seem too helpful but can't think of a better substitution.
Any advice is appreciated
Andrew
[tex]\int\cos^{5}7x\sin7xdx[/tex]
I attempted to set [tex]u=\cos^{5}7x[/tex] and ended up with (by chain rule...which I hope is correct!):
[tex]du=-35\cos^{4}7x\sin7xdx[/tex]
This doesn't seem too helpful but can't think of a better substitution.
Any advice is appreciated
Andrew