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- #1

- Thread starter jacks
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- Thread starter
- #1

- Feb 5, 2012

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Hi jacks,The value of $\sin (1^0).\sin (3^0).\sin (5^0)...........\sin (87^0).\sin (89^0)$

where all angles are in degree

I haven't found a way solve this algebraically. But if you are interested about the answer it is, \(4.0194366942304562\times 10^{-14}\)

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- #3

Thanks SudhakaraHi jacks,

I haven't found a way solve this algebraically. But if you are interested about the answer it is, \(4.0194366942304562\times 10^{-14}\)

I am trying to find it with the help of complex no.(like nth -roots of unity)

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- #4

- Feb 7, 2012

- 2,708

Follow the method used in this thread, noting that $x=\pm1^\circ,\pm3^\circ,\pm5^\circ,\ldots,\pm89 ^\circ$ are the solutions of the equation $\cos(90x) = 0.$The value of $\sin (1^0).\sin (3^0).\sin (5^0)...........\sin (87^0).\sin (89^0)$

where all angles are in degree