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Hi jacks,The value of $\sin (1^0).\sin (3^0).\sin (5^0)...........\sin (87^0).\sin (89^0)$
where all angles are in degree
Thanks SudhakaraHi jacks,
I haven't found a way solve this algebraically. But if you are interested about the answer it is, \(4.0194366942304562\times 10^{-14}\)
Follow the method used in this thread, noting that $x=\pm1^\circ,\pm3^\circ,\pm5^\circ,\ldots,\pm89 ^\circ$ are the solutions of the equation $\cos(90x) = 0.$The value of $\sin (1^0).\sin (3^0).\sin (5^0)...........\sin (87^0).\sin (89^0)$
where all angles are in degree