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HW Template missing as it was moved from another forum
A man throws a ball horizontally with an initial speed of 20 m/s. Determine the two possible angles theta 1 and theta 2 of release so that the ball strikes point B. The distance between the man and point B is 15 meters. The initial height of the ball is 1.25 meters.
Answer:
Theta 1 = 5.8 Degrees
Theta 2 = 79.4 Degrees
I know the answer, but I'm not sure how to get there. I thought about the range equation, but it doesn't seem to be working out. Any help would be much appreciated!
What I have so far:
15 = 20cos(Θ)t so, t = 15/(20cosΘ)
Answer:
Theta 1 = 5.8 Degrees
Theta 2 = 79.4 Degrees
I know the answer, but I'm not sure how to get there. I thought about the range equation, but it doesn't seem to be working out. Any help would be much appreciated!
What I have so far:
15 = 20cos(Θ)t so, t = 15/(20cosΘ)