- #1
ElBell
- 23
- 0
Please help with the below question: I have given my attempt below!
"A copper sphere of radius 2.000 cm is placed over a hole of radius 1.990 cm in an aluminum plate at 20 deg. C. At what common temperature will the sphere pass through the hole?"
My answer:
((∆T(23* 10-6)(0.01990)- .00010 = ∆T(17* 10-6)(0.02)
((∆T(23* 10-6)(0.01990) - .00010 = ∆T(17* 10-6)(0.02)
(∆T x 4.577x10^-7) – 0.00010 = (∆T x 3.4x10^-7)
- 0.00010 = (∆T x 3.4x10^-7) – (∆T x 4.577x10^-7)
-0.00010 = ∆T x -1.177 x 10^-7
∆T = 849.62
Do my equations and calcs look correct? I believed the answer was in the high 700's range...I also don't know how to bring the 20 degrees into it?
HELP!
"A copper sphere of radius 2.000 cm is placed over a hole of radius 1.990 cm in an aluminum plate at 20 deg. C. At what common temperature will the sphere pass through the hole?"
My answer:
((∆T(23* 10-6)(0.01990)- .00010 = ∆T(17* 10-6)(0.02)
((∆T(23* 10-6)(0.01990) - .00010 = ∆T(17* 10-6)(0.02)
(∆T x 4.577x10^-7) – 0.00010 = (∆T x 3.4x10^-7)
- 0.00010 = (∆T x 3.4x10^-7) – (∆T x 4.577x10^-7)
-0.00010 = ∆T x -1.177 x 10^-7
∆T = 849.62
Do my equations and calcs look correct? I believed the answer was in the high 700's range...I also don't know how to bring the 20 degrees into it?
HELP!