- #1
QuantumNet
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s = ct
The amount of motion p of the smallest particles moving in circles might or might not be mc/(2(pi)) = mv
and thereby v = c/(2(pi)) (the average value anyway, the acceleration is constant.)
since:
v0/(1 - (v/c)2)½
= v1/(1 - (v/c)2)½
we know that:
a0/(1 - (v/c)2)½ + v0/c2/(1 - (v/c)2)½
= a1/(1 - (v/c)2)½ + v1/c2/(1 - (v/c)2)½ = the acceleration.
and thereby:
a0/(1 - (v/c)2)½ + c/(2(pi))0/c2/(1 - (c/(2(pi))/c)2)½
= a1/(1 - (c/(2(pi))/c)2)½ + v1/c2/(1 - (c/(2(pi))/c)2)½ = the acceleration.
the second term (c/(2(pi)) should be the gravityconstant.
But the force of gravity decreases sphearically. So the gravityconstant we use is actually 1/(8(pi)2c).
At large range the speed of light can be aproximated to 299792458 m/s.
If anyone can confirm this, please do...
(It's easy to prove that it stands if you prove that the speed is
c/(2(pi))).
s = ct
The amount of motion p of the smallest particles moving in circles might or might not be mc/(2(pi)) = mv
and thereby v = c/(2(pi)) (the average value anyway, the acceleration is constant.)
since:
v0/(1 - (v/c)2)½
= v1/(1 - (v/c)2)½
we know that:
a0/(1 - (v/c)2)½ + v0/c2/(1 - (v/c)2)½
= a1/(1 - (v/c)2)½ + v1/c2/(1 - (v/c)2)½ = the acceleration.
and thereby:
a0/(1 - (v/c)2)½ + c/(2(pi))0/c2/(1 - (c/(2(pi))/c)2)½
= a1/(1 - (c/(2(pi))/c)2)½ + v1/c2/(1 - (c/(2(pi))/c)2)½ = the acceleration.
the second term (c/(2(pi)) should be the gravityconstant.
But the force of gravity decreases sphearically. So the gravityconstant we use is actually 1/(8(pi)2c).
At large range the speed of light can be aproximated to 299792458 m/s.
If anyone can confirm this, please do...
(It's easy to prove that it stands if you prove that the speed is
c/(2(pi))).
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