- #1
James889
- 192
- 1
Hi,
I need to solve the equation
[tex]e^z = -3[/tex]
The problems arises when i set z to a+bi
[tex]e^a(cos(b) + isin(b),~b = 0[/tex]
Then I am left with [tex]e^a = -3[/tex]
However you're not allowed to take the log of a negative number.
Also i know that [tex]cos(\pi) + isin(\pi) = -1[/tex]
Obviously [tex]3e^{(\pi*i)}[/tex] is a solution, but it's not a solution for z.
Any ideas?
I need to solve the equation
[tex]e^z = -3[/tex]
The problems arises when i set z to a+bi
[tex]e^a(cos(b) + isin(b),~b = 0[/tex]
Then I am left with [tex]e^a = -3[/tex]
However you're not allowed to take the log of a negative number.
Also i know that [tex]cos(\pi) + isin(\pi) = -1[/tex]
Obviously [tex]3e^{(\pi*i)}[/tex] is a solution, but it's not a solution for z.
Any ideas?