- #1
Safinaz
- 259
- 8
Hi there,
In Reference as hep-ph/0306037v2, we see the effective Hamiltonian of ## B \to l \nu ## equ. 1, which has the SM and the NP parts. In equ. 4, it seems that ## m_l ## comes from ## P^\mu_B ## equ. 3.
The question that how ## P^\mu_B ## yields ## m_l ## ? Where ## P^\mu_B = ( E_B, 0, 0, \bf{p} )## , or ## P^\mu_B = ( m_B, 0, 0, 0)## in B rest frame ..
Bests.
In Reference as hep-ph/0306037v2, we see the effective Hamiltonian of ## B \to l \nu ## equ. 1, which has the SM and the NP parts. In equ. 4, it seems that ## m_l ## comes from ## P^\mu_B ## equ. 3.
The question that how ## P^\mu_B ## yields ## m_l ## ? Where ## P^\mu_B = ( E_B, 0, 0, \bf{p} )## , or ## P^\mu_B = ( m_B, 0, 0, 0)## in B rest frame ..
Bests.