Taylor series of f(x)=ln(x+1) centred at 2

Then, try to find a pattern for the coefficients in front of (x-2)^n.In summary, the Taylor series of the function f(x)=ln(x+1) centered at 2 can be represented as f(2)+f'(2)(x-2)+f''(2)(x-2)^2/2!+f'''(2)(x-2)^3/3!+f''''(2)(x-2)^4/4!+...+f^{(n)}(2)(x-2)^n/n!+... with a general formula for f^{(n)}(2) and a pattern for the coefficients in front of (x-2)^n. The ln
  • #1
jmher0403
22
0

Homework Statement



Taylor series of f(x)=ln(x+1) centred at 2

Homework Equations



from 0 to infinity ∑ cn(x-a)n

cn = f(n)(a)/n!

The Attempt at a Solution



f(x) = ln(1+x)
f'(x) = 1/(1+x)
f''(x) = -1/(1+x)2
f'''(x) = 2/(1+x)3
f''''(x) = -6/(1+x)4f(2) = ln(3) = 1.0986
f'(2) = 1/3
f''(2) = -1/9
f'''(2) = 2/27
f''''(2) = -6/81

f(2)+f'(2)(x-2)+f''(2)(x-2)2/2!+f'''(2)(x-2)3/3!+f''''(2)(x-2)4/4!

I can't see any pattern except partially ..(-1)n-1(x-2)n/3nn!

I have no idea what to do with ln3

Please help!
 
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  • #2
Just write the ln3 outside of the sum. Then try to think of a pattern for the remaining terms. First, start by trying to find a general formula for [itex]f^{(n)}(2)[/itex].
 

Related to Taylor series of f(x)=ln(x+1) centred at 2

What is a Taylor series?

A Taylor series is an infinite series representation of a function, which can be used to approximate the value of a function at a specific point. It is made up of a sum of terms that are calculated using the derivatives of the function at the center point.

What is the center point in the Taylor series for f(x)=ln(x+1) centred at 2?

The center point for the Taylor series of f(x)=ln(x+1) centred at 2 is x=2. This means that the series will be centered around the point x=2 and will use derivatives of the function at x=2 to calculate the terms.

How is the Taylor series for f(x)=ln(x+1) centred at 2 calculated?

The Taylor series for f(x)=ln(x+1) centred at 2 is calculated using the formula:

f(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)^2/2! + f'''(a)(x-a)^3/3! + ...

In this case, a=2 and f(x)=ln(x+1). The derivatives of ln(x+1) can be calculated and plugged into the formula to get the Taylor series.

What is the general form of the Taylor series for f(x)=ln(x+1) centred at 2?

The general form of the Taylor series for f(x)=ln(x+1) centred at 2 is:

ln(x+1) = ln(3) + (x-2)/3 - (x-2)^2/18 + (x-2)^3/81 - (x-2)^4/648 + ...

This series can be used to approximate the value of ln(x+1) for values of x close to 2.

Why is the Taylor series for f(x)=ln(x+1) centred at 2 useful?

The Taylor series for f(x)=ln(x+1) centred at 2 is useful because it allows us to approximate the value of ln(x+1) at a specific point without having to use the original function. This can be helpful in situations where the original function is complex or difficult to work with.

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