Tangential and Radial Acceleration

In summary, a point on a rotating turntable 20.0 cm from the center accelerates from rest to a final speed of 0.700m/s in 1.75s. At t = 1.25s, the magnitude of the radial acceleration is 1.25m/s^2 and the tangential acceleration is 0.4m/s^2. The total acceleration of the point is 1.31m/s^2 at an angle of 17.7° with respect to the radial direction.
  • #1
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Homework Statement


A point on a rotating turntable 20.0 cm from the center accelerates from rest to a final speed of 0.700m/s in 1.75s. (a) At
t = 1.25s, find the magnitude and direction of the radial acceleration, (b) the tangential acceleration, and(c) the total acceleration of the point.

Homework Equations


[tex]a_t=\frac{v_f-v_i}{t}[/tex]
[tex]a_c=v^2/r[/tex]

The Attempt at a Solution


[tex]a_t=0.4m/s^2, t=1.25s→a_c=1.25m/s^2[/tex]
I don't know how to find the total accelleration, are the components of the vector [tex]a^→=(a_c, a_t)=(1.25, 0.5)m/s^2[/tex]??
 
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  • #2
Yes. Those are the components of the acceleration. What's the magnitude of that vector?
 
  • #3
the magnitude of the vector is:
[tex]sqrt((a_c)^2+(a_t)^2)=sqrt((1.25^2+0.4^2))=1.31m/s^2[/tex]
and the angle should be [tex]arctan(a_t/a_c)=arctan(0.4/1.25)=17.7°[/tex].
 
  • #4
Good. (And you caught your typo in your last equation.)

When you give the angle, be sure to specify with respect to what. A diagram helps.
 
  • #5


Your attempt at a solution is partially correct. The tangential acceleration can be calculated using the equation a_t = (v_f - v_i)/t, as you have correctly done. However, the radial acceleration cannot be calculated using the given information. It requires knowledge of the angular velocity of the turntable, which is not provided in the problem statement.

The total acceleration can be calculated using the Pythagorean theorem as a = √(a_t^2 + a_c^2). Therefore, the total acceleration at t = 1.25s is a = √(0.4^2 + 1.25^2) = 1.30 m/s^2.

Additionally, it is important to note that the direction of the radial acceleration is always towards the center of the circle, while the direction of the tangential acceleration is tangent to the circle at the given point. In this case, since the point is accelerating from rest towards the final speed, the direction of the tangential acceleration is in the same direction as the final velocity. Therefore, the total acceleration vector would be pointing towards the upper right quadrant of the circle.
 

Related to Tangential and Radial Acceleration

1. What is tangential acceleration?

Tangential acceleration is the component of acceleration that is parallel to the velocity of an object. It is a measure of how quickly the speed of an object is changing as it moves along a circular path.

2. How is tangential acceleration calculated?

Tangential acceleration can be calculated using the formula at = v2/r, where at is tangential acceleration, v is the speed of the object, and r is the radius of the circular path.

3. What is radial acceleration?

Radial acceleration is the component of acceleration that is perpendicular to the velocity of an object. It is responsible for changing the direction of an object's velocity as it moves along a circular path.

4. How is radial acceleration related to centripetal acceleration?

Radial acceleration and centripetal acceleration are closely related. Centripetal acceleration is the net acceleration towards the center of a circular path, which is made up of both radial acceleration and tangential acceleration. In fact, centripetal acceleration can be calculated using the formula ac = ar + at.

5. Can an object have both tangential and radial acceleration?

Yes, an object moving in a circular path will have both tangential and radial acceleration. Tangential acceleration determines how quickly the speed of the object changes, while radial acceleration determines the direction of the object's velocity. These two components work together to keep an object moving along a circular path.

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