- #1
skrat
- 748
- 8
Homework Statement
I basically have the radius of the circle and its displacement from the origin, so ##(x-p)^2+(y-q)^2=r^2##
And now I need to find a tangent to the circle at a given point ##(a,b)##. Or at least the slope of the tangent.
How would one do that?
Homework Equations
The Attempt at a Solution
If the circle had its center in the origin, than the slope of the tangent would be easily ##-\frac a b## but I am not sure. If the circle is not in the origin, is the slope than ##-\frac{a-p}{b-q}## or is it not?