- #1
rustynail
- 53
- 0
Hello,
I was playing around with DeMoivre's formula
ei*pi = -1
and there is something I don't quite understand about taking the natural logarithm of a certain expression. I though that
e2i*pi = 1
ln[e2i*pi] = ln (1),
but this yields to an imposibility
2i*pi = 0.
So obviously I am doing something wrong, and when I input ln[e^(2i*pi)] into Wolfram, it gives log[e2i*pi]=0.
Can anyone explain why Wolfram Alpha translates ln[e^(2i*pi)] to log[e2i*pi]=0, and why that second expression is true?
Thank you in advance for your time.
I was playing around with DeMoivre's formula
ei*pi = -1
and there is something I don't quite understand about taking the natural logarithm of a certain expression. I though that
e2i*pi = 1
ln[e2i*pi] = ln (1),
but this yields to an imposibility
2i*pi = 0.
So obviously I am doing something wrong, and when I input ln[e^(2i*pi)] into Wolfram, it gives log[e2i*pi]=0.
Can anyone explain why Wolfram Alpha translates ln[e^(2i*pi)] to log[e2i*pi]=0, and why that second expression is true?
Thank you in advance for your time.