Substitution Rule for Integrals: Solving for the Unknown Variable

In summary, the conversation discusses the relationship between integrals and functions of t and z. The main question is whether \int_a^b f(z) dt and \int_{g(a)}^{g(b)} f(z) \frac{1}{g} dz are equal. It is determined that they are not equal due to the presence of g(t) in the integral with respect to z. The conversation also discusses the relation between V_z and dz/dt, and the challenge of changing the integral from one side to the other.
  • #1
dilasluis
32
0
Hello! My problem is the following:

Is

[itex]\int_a^b f(z) dt = \int_{g(a)}^{g(b)} f(z) \frac{1}{g} dz[/itex]

?

[itex]\frac{dz}{dt} = g [/itex]

Thank you!
 
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  • #2
No. Is z a function of t?
 
  • #3
If z is a an invertible function of t such that dz/dt= g(t), then dz= g(t)dt, dt= (1/g(t))dz, but you cannot have g(t) in the integral with respect to z.
 
  • #4
z is a function of t, but not explicit, actually

[itex] V_z = \frac{dz}{dt} [/itex]

was the relation from which we took [itex] d t = \frac{dz}{V_z} [/itex].

[itex] V_z = cte [/itex]
 
Last edited:
  • #5
My biggest problem with this question is [itex] f(z) [/itex] in both sides of the equation... and how do I change the integral from left side to the right.
 

Related to Substitution Rule for Integrals: Solving for the Unknown Variable

1. What is integration by substitution?

Integration by substitution, also known as u-substitution, is a method used to simplify and solve definite and indefinite integrals. It involves replacing a complicated expression with a new variable, making the integral easier to evaluate.

2. When do we use integration by substitution?

We use integration by substitution when we have an integral that involves a function within a function, or when we have an integral that involves a composite function. It is also useful when the integrand contains a product of functions.

3. How do we perform integration by substitution?

To perform integration by substitution, we follow these steps:
1. Identify the inner function and let it equal a new variable, usually denoted by u.
2. Find the derivative of u with respect to x, du/dx.
3. Rewrite the integral in terms of u, replacing all instances of the inner function with u.
4. Substitute du/dx with du and dx with du/du.
5. Evaluate the integral in terms of u.
6. Finally, re-substitute u with the original inner function to obtain the solution in terms of x.

4. What are the benefits of using integration by substitution?

Integration by substitution allows us to solve integrals that would otherwise be difficult or impossible to evaluate. It also helps us to identify patterns and relationships between different functions, making it a useful tool for problem-solving in various fields such as physics, chemistry, and engineering.

5. Are there any limitations to integration by substitution?

Integration by substitution is not always applicable. It can only be used when the integral is in a specific form, involving a function within a function. In some cases, it may not be possible to find a suitable substitution, or the resulting integral may be just as difficult to evaluate. Additionally, it can be time-consuming and requires practice to become proficient at identifying the correct substitution.

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