- #1
bigman8424
- 25
- 0
an object mass of .5kb revovles uniformly in cirlce horizontal frictionless surface. it is attached by .75 m cord to pin set in surface. if object makes 2 complete revolujtions per second, find its speed and its centripetal force
mg = m(v2/r)
gr = v2
v = sq root of gr
v = sq root of 9.8*.75
v = 2.7 m/s2
anyone want to do me a favor, and check if I'm doing' this right,
thanks a lot..
mg = m(v2/r)
gr = v2
v = sq root of gr
v = sq root of 9.8*.75
v = 2.7 m/s2
anyone want to do me a favor, and check if I'm doing' this right,
thanks a lot..