- #1
Jaccobtw
- 163
- 32
- Homework Statement
- Solve for R. $$\frac{5}{3} = \frac{0.28 + R}{R}$$
- Relevant Equations
- Use algebra I guess
The variable is already isolated on one side. I dont' know how to solve for R though. Any help? Thank you.
Fractions are always a problem. Get rid of them!Jaccobtw said:Homework Statement:: Solve for R. $$\frac{5}{3} = \frac{0.28 + R}{R}$$
Relevant Equations:: Use algebra I guess
The variable is already isolated on one side. I dont' know how to solve for R though. Any help? Thank you.
Ah ok. Multiply both sides by R and then subtract R from both sides. The rest is cakePeroK said:Fractions are always a problem. Get rid of them!
Better yet, multiply both sides of the equation by 3R, and then isolate the terms with R on one side.Jaccobtw said:Ah ok. Multiply both sides by R and then subtract R from both sides. The rest is cake
Although R is only on the right-side, I would not describe that R as "isolated".Jaccobtw said:Homework Statement:: Solve for R. $$\frac{5}{3} = \frac{0.28 + R}{R}$$
Relevant Equations:: Use algebra I guess
The variable is already isolated on one side. I dont' know how to solve for R though. Any help? Thank you.
While true, it may be better to simplify [to reduce the number of R's one sees on]lurflurf said:the difficulty here is R appears twice
we can either merge the R's or eliminate one
to do the later we can...
subtract one from both sides
$$\frac{5}{3} = \frac{0.28 + R}{R}$$
$$\frac{5}{3} -\frac{3}{3}= \frac{0.28 + R}{R}-\frac{R}{R}$$
Solving for R means finding the value of the variable R in an algebraic equation. This involves rearranging the equation and performing operations to isolate R on one side of the equation.
The operations used to solve for R will depend on the specific equation. In general, you will need to use inverse operations, such as addition and subtraction, multiplication and division, and exponentiation and logarithms, to undo the operations that are currently being performed on R.
Yes, you can still solve for R if it is in an exponent or logarithm. You will need to use the inverse operation of the exponent or logarithm, such as taking the logarithm or raising to a power, to isolate R.
If you have multiple R's in your equation, you will need to combine like terms and use the distributive property to simplify the equation. Then, you can use the same steps as before to isolate R on one side of the equation.
There is no specific order in which you should solve for R, as long as you are using the correct operations and following the rules of algebra. However, it is often helpful to start by simplifying the equation and then working towards isolating R.